WebJul 26, 2024 · answered Jul 26, 2024 by Gargi01 (50.9k points) selected Aug 30, 2024 by Haifa Best answer Let the first term of the AP be a and the common difference be d Given: Sm = m2p and Sn = n2p To prove: Sp = p3 According to the problem (m - n)d = 2p (m - n) Now m is not equal to n So d = 2p Substituting in 1st equation we get Hence proved. WebMZ ÿÿ¸@ º ´ Í!¸ LÍ!This program cannot be run in DOS mode. $Þ#òªšBœùšBœùšBœùõ]—ù™Bœù ^’ù’Bœùõ]–ù‘Bœùõ]˜ù˜Bœù JÃù›BœùšB ù Bœù JÁù“Bœù¬d—ùÙBœù¬d–ù™Bœù ß6ù‘Bœù ß ù›Bœù]Dšù›BœùRichšBœùPEL @ çZà/ ˜ N² ° @ @ X¤ ´á x0 , ° ° .textõ– ˜ `.rdata :° œ @@.datað#ð Ø @À.sxdata Ú @ À.rsrc ...
If Sm = m2p and Sn = n2p, where m ≠ n in an AP then prove
WebOct 21, 2024 · Best answer Given: Sn = n2p and Sm = m2p To Prove: Sp = p3 We know that, ⇒ 2mp = 2a + (m – 1)d ⇒ 2mp – (m – 1)d = 2a … (ii) From eq. (i) and (ii), we get ⇒ 2np – (n – 1)d = 2mp – (m – 1)d ⇒ 2np – nd + d = 2mp – md + d ⇒ 2np – nd = 2mp – md ⇒ md – nd = 2mp – 2np ⇒ d (m – n) = 2p (m – n) ⇒ d = 2p … (iii) Putting the value of d in eq. (i), we get WebIn an A.P. the sn= n²p and sm =m²p,m not equal to n then, prove that sp= p³ Sn =n2p and Sm =m2p,m =n, in an AP, prove that Sp =p3 - Toppr1 जवाबClick here to ... hildebrand actress
If in an A.P., Sn = qn2 and Sm = qm2, where Sr denotes the sum of …
WebApr 8, 2004 · Tryptic digestion of HCMV particles. HCMV particles were denatured by the addition of urea to 8 M and heating to 37°C for 30 min. The sample was then diluted fourfold with 100 mM ammonium bicarbonate (AB), and CaCl 2 was added to 1 mM. Methylated, sequencing-grade porcine trypsin (Promega, Madison, Wis.) was added at a substrate-to … WebMar 26, 2024 · If in an A.P., Sn = q n^2 and Sm = qm^2, where Sr denotes the sum of r terms of the A.P., then Sq equals asked Aug 20, 2024 in Mathematics by AsutoshSahni ( 53.4k … WebMar 30, 2024 · We know that Sn = n/2 ( 2a + (n 1)d ) Where, Sn = sum of n terms of A.P. n = number of terms a = first term and d = common difference Thus, Sum of n terms = Sn = /2 (2a + (n 1)d) And Sum of m terms = Sm = /2 (2a + (m 1)d) It is given that, ratio of the sums of m and n terms of an A.P. is m2: n2 (Sum of m terms )/ (Sum of n terms) = m2/n2 (Sm )/ … hildebrand and sons