WebJul 20, 2024 · def replace (lst, dictionary): for k,v in enumerate (lst): if v in dictionary: lst [k] = dictionary [v] return lst. For each item in the list, k is the index of the value and v is the value itself. You then check if the value is in the dictionary, and if it is, you replace the value in the list with the value in the dictionary. WebAug 21, 2024 · I managed to figure this out on my own -- I played around a bit and got the keys and values to switch with dict2 = {keys: old_keys for old_keys, old_values in dict.items() for keys in old_values}, then used df.columnheader.replace(dict2) to get what I needed. This question here helped me, then I used pd.Series.replace.Thanks! – florence-y
Python – Replace dictionary value from other dictionary
WebDec 21, 2024 · Note: for Python 3 users, you should use .keys () instead of .iterkeys (): dictionary = {"NORTH":"N", "SOUTH":"S" } for key in dictionary.keys (): address = address.upper ().replace (key, dictionary [key]) Share Improve this answer Follow edited Feb 18, 2024 at 12:48 CharlesG 330 3 12 answered Jan 4, 2013 at 11:44 Samuele … WebOct 15, 2016 · My question pertains to Python 3.x, where I am trying to basically access a value in a very small dictionary (3 keys, 1 value each). I have searched high and low on the web (and on here), but cannot seem to find anything pertaining to replacing a value in a dictionary. I have found the "replace" function, but does not seem to work for dictionaries. rbc truro hours
How to replace existing key in a dictionary in python?
Webdef appendabc (somedict): return dict (map (lambda (key, value): (str (key)+"abc", value), somedict.items ())) def transform (multilevelDict): new = appendabc (multilevelDict) for key, value in new.items (): if isinstance (value, dict): new [key] = transform (value) return new print transform ( {1:2, "bam":4, 33: {3:4, 5:7}}) WebNov 10, 2024 · In case of renaming all dictionary keys: target_dict = {'k1':'v1', 'k2':'v2', 'k3':'v3'} new_keys = ['k4','k5','k6'] for key,n_key in zip (target_dict.keys (), new_keys): target_dict [n_key] = target_dict.pop (key) Share Improve this answer edited Nov 8, 2024 at 9:09 Dave Liu 781 1 10 29 answered Jun 17, 2024 at 12:29 Ikbel 1,657 1 14 30 3 WebDec 3, 2024 · First, you need to swap keys and values in your dictionary: from operator import itemgetter dct = {"a": 1, "b": 2, "c": 3} lst = [2, 3, 1] dct = {v: k for k, v in dct.items ()} # {1: 'a', 2: 'b', 3: 'c'} print (list (itemgetter (*lst) (dct))) # ['b', 'c', 'a'] Share Improve this answer Follow answered Dec 3, 2024 at 10:51 Mykola Zotko rbc truro phone number